Respuesta :

[tex]\begin{gathered} \frac{x}{6}\text{ + 3 }\ge\text{ -2} \\ \frac{x}{6}\text{ }\ge-2-3 \\ \frac{x}{6}\text{ }\ge-5 \\ \frac{x}{6}\text{ }\ge\frac{-5}{1} \\ multiply\text{ both side by the LCM 6} \\ 6\times\frac{x}{6}\text{ }\ge\frac{-5}{1}\times6 \\ x\text{ }\ge\text{ -30} \end{gathered}[/tex]

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