The force acting on the toy is,
[tex]F=4.63\text{ N}[/tex]
As the toy is moving with the constant speed,
So acceleration of the toy is zero.
According to the Newton's Law,
[tex]\begin{gathered} F_{net}=ma \\ F_{net}=0 \end{gathered}[/tex]
Thus, the force acting in the horizontal direction is equal to the friction force acting on the toy.
[tex]\begin{gathered} F_{friction}=-F\cos (63^{\circ}) \\ F_{friction}=-4.63\times\cos (63^{\circ}) \\ F_{friction}=-2.10\text{ N} \end{gathered}[/tex]
Thus, the force of friction acting on the toy is 2.10 N in the opposite direction of the motion of the toy.
