[tex]\angle JLK=60^0[/tex]
1) When we are dealing with a Rhombus is convenient to recall some properties:
0. Opposite angles are congruent
,
1. Consecutive angles are supplementary
,
2. Congruent sides
,
3. Diagonals bisect angles
,
4. Diagonals are perpendicular.
So, we can sketch out the following, to better grasp it:
2) So, based on the properties: Opposite angles are congruent, and the fact that Diagonals bisect angles then we can state the following answer:
[tex]\angle JLK=60^0[/tex]
