Answer:
The volume of the ballon is 4.48L.
Explanation:
1st) It is necessary to make sure that all the variables units are in atm, L, mol and K. So, we have to convert 0.00°C to K:
[tex]0.00+273.15=275.15K[/tex]
2nd) With the ideal gas formula, we can replace the values of pressure, number of moles and temperature, to calculate the volume of the helium gas in the ballon:
[tex]\begin{gathered} P*V=n*R*T \\ 1.00atm*V=0.200mol*0.082\frac{atm*L}{mol*K}*273.15K \\ 1.00atm*V=4.48atm*L \\ V=\frac{4.48atm*L}{1.00atm} \\ V=4.48L \end{gathered}[/tex]
R in the formula is the ideal gas constant, and it is equal to 0.082 atm*L/mol*K.
So, the volume of the ballon is 4.48L.
