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[tex] \frac{3}{2x} - \frac{1}{8 {x}^{2} } [/tex]If possible, a step by step for this would help immensely so I could do the rest of the problems like this one.

Respuesta :

Problem

Solution

For this case we can take common factor in the denominator 2x and we got:

[tex]\frac{1}{2x}(\frac{3}{1}-\frac{1}{4x})[/tex]

Then we can solve the fractions with this operation:

[tex]\frac{1}{2x}(\frac{3\cdot4x-1\cdot1}{1\cdot4x})=\frac{1}{2x}(\frac{12x-1}{4x})[/tex]

then we can simplify on this way:

[tex]\frac{12x-1}{6x^2}[/tex]

Ver imagen AmethystF720849