How many moles of potassium bromide is needed to produced 51.62 moles of bromine?

Answer
Option A = 103.2 mol KBr
Explanation
Given:
[tex]Cl_2+2KBr\rightarrow2KCl+Br_2[/tex]Moles of bromine = 51.62 moles
Required: Moles of KBr
Solution
Use the stoichiometry to calculate the the moles of KBr
The molar ration between Br and KBr is 1:2
Therefore the moles of KBr = 51.62 mol x 2 = 103.24 mol