Since QS and PR bisect each other at point T, triangles QTP and RTS are similar. Hence, we ca draw the following picture:
and we can see that x+48 must be equal to 2x:
[tex]2x=x+48[/tex]
and we can solve this equation for the unknow x as
[tex]\begin{gathered} 2x-x=48 \\ x=48 \end{gathered}[/tex]
Now, with the value x, the angle P is equal to
[tex]\begin{gathered} P=48+48 \\ P=96 \end{gathered}[/tex]
and the answer is a.
