ANSWER
Option 3: 21.3 in²
EXPLANATION
Let's draw a diagram of the triangle ABC,
When two sides and the included angle are given, we can find the area as half the product of the side lengths and the sine of the included angle,
[tex]A=\frac{1}{2}\cdot b\cdot c\cdot\sin(A)[/tex]Replace the known values and solve,
[tex]A=\frac{1}{2}\cdot13.2in\cdot7.3in\cdot\sin(26.3\degree)\approx21.3in^2[/tex]Hence, the area of triangle ABC is 21.3 in², rounded to the nearest tenth.
