we have the expression
[tex](x-2)^{15}[/tex]
Applying the Binomial Theorem
Remember that
the coefficient of each term r of the expansion 0f (x+y)^n is given by C(n, r - 1).
so
For the first term, the coefficient is C(15,0) -----> 1
For the second term, the coefficient is C(15,1) -----> 14
For the third term, the coefficient is C(15,2) ----> 105
For the fourth term, the coefficient is C(15,3) ---> 455
therefore
the first three terms are
[tex]\begin{gathered} (x-2)^{15}=(1)x^{15}+14x^{14}(-2)+105x^{13}(-2)^2 \\ (x-2)^{15}=x^{15}-28x^{14}+420x^{13} \end{gathered}[/tex]
