Start by sketching the rectangle
write the area as an equation
[tex]\begin{gathered} A=L\cdot W \\ 42=(x)(2x+5) \\ 42=2x^2+5x \end{gathered}[/tex]write the expression in the form of a quadratic expression
[tex]ax^2+bx+c=0[/tex][tex]2x^2+5x-42=0[/tex]solve the equation using the quadratic equation
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]x=-6; x=3.5
since we are talking about meassurements it cannot be a negative, so the solution must be 3.5
Dimensions of the rectangles
Lenght: (2x+5) = 12
Width: 3.5
