Given the function f(x) as follows:
[tex]f(x)=3x^2(x-2)(x^2-25)[/tex]
We will find the zeros of the function as follows:
[tex]\begin{gathered} f(x)=0 \\ 3x^2(x-2)(x^2-25)=0 \\ 3x^2=0\rightarrow x=0 \\ or \\ x-2=0\operatorname{\rightarrow}x=2 \\ or \\ x^2-25=0 \\ (x-5)(x+5)=0 \\ x-5=0\operatorname{\rightarrow}x=5 \\ x+5=0\operatorname{\rightarrow}x=-5 \end{gathered}[/tex]
So, the answer will be, the zeros of the function will be as follows:
x = 0
x = 2
x = -5
x = 5
