Given data:
The given value of cos(θ)= -0.25.
The value of sin(θ) is,
[tex]\begin{gathered} \cos ^2(\theta)+\sin ^2(\theta)=1 \\ \sin ^2(\theta)=1-\cos ^2(\theta) \\ \sin (\theta)=\sqrt[]{1-(-0.25)^2} \\ =\sqrt[]{1-0.0625} \\ =0.968 \\ \approx0.97 \end{gathered}[/tex]
The value of sine function is positive in the second quadrant tha is when θ lies between π/2 to π.
Thus, the value of sin(θ) is 0.97.
