The cost of three cans of dog food and two raw hide bones is, 6.80
If the customer buys four cans of dog food but returns one raw hide bone the cost is 7.25.
So, Let x be the cost of one can of dog food and y be the cost of one raw hide bone. Then we have,
[tex]\begin{gathered} 3x+2y=8.60\ldots\text{.}(1) \\ 4x=7.25\ldots\text{.}(2) \end{gathered}[/tex]From the equation 2 we get,
[tex]x=\frac{7.25}{4}=1.8125\approx2[/tex]Substituting the value of x in equation 1, we get,
[tex]\begin{gathered} 3\times\frac{7.25}{4}+3y=8.60 \\ 3\times1.8125+3y=8.60 \\ 3y=8.6-5.4375=3.1625 \\ y=\frac{3.1625}{3}=1.05\approx1 \\ \end{gathered}[/tex]