You can find the probability of; no blue balls drawn and and then subtract p(no blue) from 1
P(no blue) = 2/3 * 2/4 * 2/5 = 8/60
P(no blue) = 4/30
P(at least 1 blue) =
[tex]=1-\frac{4}{30}[/tex][tex]=\frac{30-4}{30}[/tex][tex]=\frac{26}{30}[/tex][tex]=\frac{13}{15}[/tex]
