The work output of the procedure is given as,
[tex]W_O=wh[/tex]Substitute the known values,
[tex]\begin{gathered} W_O=(60\text{ N)(3 m)(}\frac{1\text{ J}}{1\text{ Nm}}) \\ =180\text{ J} \end{gathered}[/tex]Thus, the work output is 180 J.
The work input of the procedure is,
[tex]W_i=Fd[/tex]Substitute the known values,
[tex]\begin{gathered} W_i=(25\text{ N)(10 m)(}\frac{1\text{ J}}{1\text{ Nm}}) \\ =250\text{ J} \end{gathered}[/tex]Thus, the work input is 250 J.
The efficiency of the person is given as,
[tex]e=\frac{W_O}{W_i}[/tex]Substitute the known values,
[tex]\begin{gathered} e=\frac{180\text{ J}}{250\text{ J}} \\ =0.72 \end{gathered}[/tex]Thus, the efficiency of person is 0.72 or 72%.
