We need to follow the formula to find the size of the bacterial population is,
[tex]y=a(b)^t[/tex]
Here, t is the total amount of bacteria, a is the initial bacteria at time = 0, abd b is the growth factor ( which is 2 according to the question )
At t = 110 mins , y = 60,000 we have
[tex]60,000=a(2)^{\frac{110}{15}}[/tex][tex]\begin{gathered} a=\frac{60000}{2^{7.33}} \\ a=372.92 \end{gathered}[/tex]
Now, the size of the population after 3 hours
[tex]2^{\frac{3\times60}{15}}p=2^{12}p[/tex][tex]\begin{gathered} 2^{12}\times372.92=4096\times372.92 \\ =1,527,480.32 \end{gathered}[/tex]
The answer is 1,527,480.32
