Given:
Given that the two angles and one side of a triangle.
[tex]\begin{gathered} \angle A=42 \\ \angle B=61 \\ a=13cm \\ b=xcm \end{gathered}[/tex]
Required:
To find the value of x.
Explanation:
Now from the law of sine,
[tex]\frac{\sin A}{a}=\frac{\sin B}{b}[/tex][tex]\frac{\sin42}{13}=\frac{\sin61}{x}[/tex][tex]\frac{0.6691}{13}=\frac{0.8764}{x}[/tex][tex]0.0514=\frac{0.8764}{x}[/tex][tex]\begin{gathered} x=\frac{0.8764}{0.0514} \\ \\ x=17cm \end{gathered}[/tex]
Final Answer:
The option C is correct.
The value of x = 17 cm.
