Given:
[tex]\frac{1}{2}x=5,x+11=3.x-3=-8,\text{ and }2x-1=19.[/tex]Required:
We need to find the value for x.
Explanation:
1)
[tex]\frac{1}{2}x=5[/tex]Multiply both sides of the equation by 2.
[tex]2\times\frac{1}{2}x=2\times5[/tex]Cancel out the common multiple 2 on the left-hand side of the equation and multiply 2 and 5 on the right-hand side of the equation.
[tex]x=10[/tex]2)
[tex]x+11=3[/tex]Subtract 11 from both sides of the equation.
[tex]x+11-11=3-11[/tex][tex]x+0=-8[/tex][tex]x=-8[/tex]3)
[tex]x-3=-8[/tex]Add 3 on both sides of the equation.
[tex]x-3+3=-8+3[/tex][tex]x+0=-5[/tex][tex]x=-5[/tex]4)
[tex]2x-1=19[/tex]Add 1 on both sides of the equation.
[tex]2x-1+1=19+1[/tex][tex]2x+0=20[/tex][tex]2x=20[/tex]Divide both sides of the equation by 2.
[tex]\frac{2x}{2}=\frac{20}{2}[/tex]Cancel out the common multiple 2.
[tex]x=10[/tex]Final answer:
1) x=10
2) x=-8
3) x=-5
4) x =10