The perimeter of the parallelogram can be calculataed as,
[tex]P=2(a+b)[/tex]
Here,
[tex]\begin{gathered} a=10-x+\frac{4}{9}y \\ b=\frac{7}{8}x+\frac{2}{9}y \end{gathered}[/tex]
Therefore,
[tex]\begin{gathered} P=2(10-x+\frac{4}{9}y+\frac{7}{8}x+\frac{2}{9}y) \\ =2((-1+\frac{7}{8})x+\frac{7}{9}y) \\ =-\frac{1}{4}x+\frac{14}{9}y \end{gathered}[/tex]
