Respuesta :

we have the expression

[tex]\int x^2sin(3x)dx=-\frac{1}{3}x^2cos(3x)+\frac{2}{27}(3xsin(3x)+cos(3x))+C[/tex]

Rewrite the solution

[tex]\frac{2}{9}xsin(3x)-(\frac{1}{3}x^2-\frac{2}{27})(cos(3x)+C[/tex]

therefore

The answer is the first option

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