Respuesta :
ANSWER
13.06 m
EXPLANATION
The maximum height of an object that is thrown upward is reached when its velocity is zero. This is because the object stops for a moment before changing direction and start falling down.
First we have to find the time it takes for the pellet to reach the maximum height:
[tex]v=u-gt[/tex]u is the initial velocity 16m/s and g is the acceleration of gravity, which is negative because is opposite to the direction of motion. The final velocity v is zero, as stated before:
[tex]0=u-gt[/tex]Solving for t:
[tex]\begin{gathered} u=gt \\ t=\frac{u}{g} \end{gathered}[/tex]If we consider g = 9.8m/s²:
[tex]t=\frac{16m/s}{9.8m/s^2}\approx1.63s[/tex]Now we can find what is the height of the pellet at that time:
[tex]y=ut-\frac{1}{2}gt^2[/tex]Replacing with the information we have:
[tex]y=16m/s\cdot1.63s-\frac{1}{2}\cdot9.8m/s^2\cdot1.63^2s^2=13.06m[/tex]The pellet's maximum height is 13.06 m
