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 The vertices of ΔABC are A(−2,4), B(−2,5), and C(−5,2). If ΔABC is reflected across the line y=1 to produce the image ΔA'B'C', and the coordinates of the vertex B'.The coordinates of B' after a reflection across the line y=1 are

The vertices of ΔABC are A24 B25 and C52 If ΔABC is reflected across the line y1 to produce the image ΔABC and the coordinates of the vertex BThe coordinates o class=

Respuesta :

A reflection across the y = 1 consists:

T(x,y) => T'( x, 1 - (y - 1) )

then, for the given points, you obtain:

(-2,5) => (-2 , 1 - (5 - 1)) = (-2 , 1 - 4) = (-2 ,-3)

(-2,4) => (-2, 1 - (4 - 1)) = (-2 , 1 -3) = (-2 ,-2)

(-5,2) => (-5 , 1 - (2 -1)) = (-5, 1 - 1) = (-5 , 0)

Hence, the coordinates of point B' are (-2,-3)

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