ANSWER
[tex]\begin{equation*} 9.29*10^8J \end{equation*}[/tex]EXPLANATION
First, let us find the total mass of the blocks of ice:
[tex]\begin{gathered} m=137*3 \\ m=411\text{ }kg \end{gathered}[/tex]To find the amount of heat that must be gained, apply the formula for the heat change due to vaporization:
[tex]\Delta Q=mh_v[/tex]where hv = heat of vaporization = 2.26 * 10⁶ J/kg
Therefore, the amount of heat that must be gained is:
[tex]\begin{gathered} \Delta Q=411*2.26*10^6 \\ \Delta Q=928.86*10^6J \\ \Delta Q=9.29*10^8J \end{gathered}[/tex]That is the answer.
