Given the following sum:
[tex]9\frac{3}{16}+7\frac{5}{8}[/tex]First let's convert these mixed numbers into improper fractions:
[tex]\begin{gathered} 9\frac{3}{16}=\frac{9(16)+3}{16}=\frac{144+3}{16}=\frac{147}{16} \\ 7\frac{5}{8}=\frac{7(8)+5}{8}=\frac{56+5}{8}=\frac{61}{8} \end{gathered}[/tex]then, we would have the following equivalent expression:
[tex]9\frac{3}{16}+7\frac{5}{8}=\frac{147}{16}+\frac{61}{8}[/tex]now, notice that we can write 61/8 like this:
[tex]\frac{61}{8}=\frac{122}{16}[/tex]then, we have that:
[tex]\frac{147}{16}+\frac{61}{8}=\frac{147}{16}+\frac{122}{16}=\frac{147+122}{16}=\frac{269}{16}=16\frac{13}{16}[/tex]therefore, the result of the sum is 16 13/16
