Respuesta :

Answer

0.422 M NaOH solution.

Explanation

Given:

Volume of NaOH solution, Vb = 23.7 mL

Volume of HCl solution, Va = 20.0 mL

Concentration of HCl solution, Ca = 0.500 M

What to find:

The concentration of NaOH solution.

Step-by-step solution:

Step 1: Write a balanced equation for the reaction to determine the mole ratio.

Equation: HCl + NaOH -----> NaCl + H₂O

Mole ratio: 1 1

Step 2: Calculate the concentration of NaOH solution.

The concentration of NaOH solution can be calculated using the formula below.

[tex]\begin{gathered} \frac{C_aV_a}{n_a}=\frac{C_bV_b}{n_b} \\ \\ \Rightarrow C_b=\frac{C_a\times V_a\times n_b}{V_b\times n_a} \end{gathered}[/tex]

Putting the values of the given parameters into the formula, we have;

[tex]C_b=\frac{0.500M\times20.0mL\times1}{23.7mL\times1}=\frac{10M}{23.7}=0.422\text{ }M[/tex]

Therefore, the concentration of NaOH solution to neutralize 20.0 mL f 0.500 M HCl solution is 0.422 M

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