Given:
A car is purchased for $33,000.
Each year it loses 30% of its value
The value of the car (y) after (x) years will be as follows:
[tex]y=33000(1-\frac{30}{100})^x[/tex]We will find (x) when y = 4900
[tex]\begin{gathered} 4900=33000(1-\frac{30}{100})^x \\ \frac{4900}{33000}=0.7^x \\ \\ ln(\frac{4900}{33000})=x*ln(0.7) \\ \\ x=\frac{ln(\frac{4900}{33000})}{ln(0.7)}=5.347 \end{gathered}[/tex]Rounding to the smallest possible whole number
So, the answer will be the number of years = 5
