How much farther (to the nearest meter) does the airplane have to fly before it is directly above the coastline?

SOLUTION:
Case: Trigonometry
Method;
The diagram
The coastline is C
The distance further is 'x'
The Airplane is A.
To find x
[tex]\begin{gathered} \tan14\degree=\frac{6000}{x} \\ x=\frac{6000}{\tan14\degree} \\ x=\frac{6000}{0.2493} \\ x=24064.69\text{ }m \end{gathered}[/tex]Final answer: Nearest meter
24065 m