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Two cows are getting ready to jump over the moon. The height, h, in feet of one cow after t seconds is given by the equation h(t) = -8t^2 + 56t + 160. The height of the other cow is given by the equation h(t) = -8t^2 + 97t. After how many seconds are the cows at the same height?

Two cows are getting ready to jump over the moon The height h in feet of one cow after t seconds is given by the equation ht 8t2 56t 160 The height of the other class=

Respuesta :

Given:

The equations for height of cows is,

[tex]h(t)=-8t^2+56t+160[/tex][tex]h(t)=-8t^2+97t[/tex]

Explanation:

For the same height the equation are equal. So,

[tex]\begin{gathered} -8t^2+56t+160=-8t^2+97t \\ 97t-56t=160 \\ 41t=160 \\ t=\frac{160}{41} \\ =3.90243 \\ \approx3.902 \end{gathered}[/tex]

So after 3.902 seconds two cows are at the same height.

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