Respuesta :
the Given
*The number of mol of neon is n = 1 mol.
*The temperature of the neon gas is T = 288 K.
*The mass of the neon gas is m = 0.01 kg.
*The gas constant R is R = 8.31 J/(mol.K).
To find: The average velocity of atoms of neon (v).
According to the given equation,
[tex]\frac{1}{2}mv^2=\frac{3}{2}nRT[/tex]Substitute the known values.
[tex]\begin{gathered} \frac{1}{2}\times0.01\text{ kg}\times v^2=\frac{3}{2}\times1\text{ mol}\times8.31\text{ J/mol.K}\times288\text{ K} \\ 5\times10^{-3}\text{ kg}\times v^2=\frac{3}{2}\times2393.28\text{ J} \\ 5\times10^{-3}\text{ kg}\times v^2=3589.92\text{ J}\times\frac{1\frac{kg.m^2}{s^2}}{1\text{ J}} \\ v^2=\frac{3589.92\text{ }\frac{kg.m^2}{s^2}}{5\times10^{-3}\text{ kg}} \\ v^2=717984\frac{m^2}{s^2} \\ v=\sqrt[]{717984\frac{m^2}{s^2}} \\ v=847.33\text{ m/s} \\ v\cong847\text{ m/s} \end{gathered}[/tex]The average velocity of atoms of neon is 847.33 m/s. Thus, option (A) is the correct answer.
