Let's start fresh.
Solve the first equation for y:
[tex]\begin{gathered} 3x-y=-8 \\ 3x+8=y \\ or \\ y=3x+8 \end{gathered}[/tex]
Now, substitute it into 2nd equation and then solve for x:
5x + 2y = 5
5x + 2(3x + 8) = 5
5x + 6x + 16 = 5
11x = 5 - 16
11x = -11
x = -11/11
x = -1
[tex]\begin{gathered} 5x+2y=5 \\ 5x+2(3x+8)=5 \\ 5x+6x+16=5_{}_{} \\ 11x=5-16 \\ 11x=-11 \\ x=-\frac{11}{11} \\ x=-1 \end{gathered}[/tex]
We knew,
y = 3x + 8
We plug the value of x and get y:
y = 3x + 8
y = 3(-1) + 8
y = -3 + 8
y = 5
Hence, the solution of the system is:
x = - 1
y = 5
