Step 1
Tree diagram for total possible outcomes.
Step 2
Total possible outcome = { 1H, 2H, 3H, 4H, 5H, 6H, 1T, 2T, 3T, 4T, 5T, 6T}
Total possible outcome = 12
Required outcome = {3H , 6H } = 2
Step 3
[tex]\begin{gathered} \text{Probability of m ultiple of 3 and head= }\frac{n\text{ umber of required outcome}}{n\text{ umber of possible outcome}} \\ \\ =\text{ }\frac{2}{12} \\ =\text{ }\frac{1}{6} \end{gathered}[/tex]
