Given:
The frequency of photon is 9.48 × 10^13 Hz.
To find:
The energy of a photon.
Explanation:
The energy of a photon is related to its frequency as,
[tex]E=h\nu[/tex]here, h is called Planck's constant whose value is 6.63 × 10^(-34) J s, and ν is the frequency of the photon.
Substituting the values in the above equation, we get:
[tex]E=6.63\times10^{-34}\text{ J}\cdot\text{s}\times9.48\times10^{13}\text{ Hz}[/tex]Simplifying above equation, we get:
[tex]E=6.28\times10^{-20}\text{ J}[/tex]Thus, the value of the photon's energy is 6.28 × 10^(-20) J.
Final answer:
The energy of photon is 6.28 × 10^(-20) J.