The given multiplication can be expressed as,
[tex](3p-7)(2p^2-3p-4)[/tex]On multiplying, we get,
[tex]\begin{gathered} (3p-7)(2p^2-3p-4)=(3p\times2p^2)-(3p\times3p)-(4\times3p)-(7\times2p^2)+(7\times3p)+(7\times4) \\ =6p^3-9p^2-12p-14p^2+21p+28 \\ =6p^3-23p^2+9p+28 \end{gathered}[/tex]Thus, the third option is correct.
