Respuesta :

Starting with the expression:

[tex]\frac{45w^8}{9w^2}[/tex]

Write the fraction as the product of 45/9 and the fraction involving the variable w:

[tex]\frac{45w^8}{9w^2}=\frac{45}{9}^{}\cdot\frac{w^8}{w^2}[/tex]

Notice that 45/9=5. Then:

[tex]\frac{45}{9}\cdot\frac{w^8}{w^2}=5\cdot\frac{w^8}{w^2}[/tex]

Recalling the laws of exponents:

[tex]\frac{a^n}{a^m}=a^{n-m}[/tex]

Then:

[tex]\begin{gathered} 5\cdot\frac{w^8}{w^2}=5\cdot w^{8-2} \\ =5\cdot w^6 \end{gathered}[/tex]

Therefore:

[tex]\frac{45w^8}{5w^2}=5w^6[/tex]