Answer:
The sum of the missing values is;
[tex]P(X=0)+P(X=3)=0.1[/tex]
Explanation:
Given the probability distribution table in the attached image.
[tex]\begin{gathered} P(X=1)=0.6 \\ P(X=2)=0.3 \end{gathered}[/tex]
So, we have;
[tex]\begin{gathered} P(X=0)+P(X=3)=1-(P(X=1)+P(X=2)) \\ P(X=0)+P(X=3)=1-(0.6+0.3) \\ P(X=0)+P(X=3)=1-(0.9) \\ P(X=0)+P(X=3)=0.1 \end{gathered}[/tex]
Therefore, the sum of the missing values is;
[tex]P(X=0)+P(X=3)=0.1[/tex]
