Answer
: 0.13 moles of KClExplanation:
The balanced chemical reaction :
[tex]10KClO_3+3P_4\Rightarrow3P_4O_{10}+\text{ 10KCl }[/tex]
GIVEN
• Mass of Potassium chlorate KClO3 = 16 g
,
• Molecular mass KClO3 = 122,55 g/mol
(1) Calculate moles of KClO3
[tex]\begin{gathered} Moles\text{ = }\frac{Mass\text{ KClO}_3}{Molecular\text{ Mass KClO}_3} \\ \text{ = }\frac{16g\text{ }}{122.55\text{ g.mol}^{-1}} \\ \text{ =0.131 moles of KClO}_3 \end{gathered}[/tex]
(2) By stoichiometry, the balanced equation informs us that :
10 moles KClO3 produces 10 moles KCl
therefore ;
0.131 moles of KClO3 will produce 0.13 moles of KCl
{ take note that the ratio if 1:1 , meaning for every 1 mole of KClO3 , 1 mole of KCL willbe produced }
