Approximately 16.28 cm
1) We can sketch out this triangle to better figure out:
2) So now, let's resort to the Pythagorean Relation:
[tex]\begin{gathered} a^2=b^2+c^2 \\ a^2=11^2+12^2 \\ a^2=121+144 \\ a^2=265 \\ a=\sqrt{265} \\ a\approx16.28 \end{gathered}[/tex]Note that the hypotenuse is always on the left, in the Pythagorean Theorem.
