Given:
y=5x-10
y=3x+8
To find the values of x and y using substitution,we substitute y=5x-10 into the second equation (y=3x+8). So,
[tex]\begin{gathered} 5x-10=3x+8 \\ \text{Simplify and rearrange} \\ 5x-3x=8+10 \\ 2x=18 \\ x=\frac{18}{2} \\ \text{Calculate} \\ x=9 \end{gathered}[/tex]
Next, we substitute the value of x in one of the original equations. We plug in x=9 into y=5x-10:
[tex]\begin{gathered} y=5x-10 \\ y=5(9)-10 \\ \text{Simplify} \\ y=45-10 \\ y=35 \end{gathered}[/tex]
Therefore, the answer in ordered pair is:
(x,y)=(9,35)
