Respuesta :

The given inequalities are

- a/4 > 3

b - 12 > - 3

For the first inequality,

- a/4 > 3

- a > 4 x 3

- a > 12

If we divide both sides of the inequality by - 1, the symbol reverses. thus, we have

a < - 12

For the esecond inequality,

b - 12 > - 3

b > - 3 + 12

b > 9

The values of a are all numbers less than - 12

The values of b are all numbers greater than 9

there is no value that it common to these sets of numbers. Thus, no value makes both inequalities true