Given:
The side of the triangle are
[tex]\begin{gathered} a=5\sqrt{125}in \\ \\ b=4\sqrt{180}in \\ \\ c=\sqrt{147}in \end{gathered}[/tex]
Required:
To find the perimeter of the triangle.
Explanation:
The formula for perimeter is
[tex]P=a+b+c[/tex]
Here
[tex]\begin{gathered} P=5\sqrt{125}+4\sqrt{180}+\sqrt{147} \\ \\ =5\sqrt{25\times5}+4\sqrt{9\times20}+\sqrt{49\times3} \\ \\ =5\times5\sqrt{5}+4\times3\sqrt{20}+7\sqrt{3} \\ \\ =25\sqrt{5}+12\sqrt{20}+7\sqrt{3} \end{gathered}[/tex]
