Given that two balls undergo elastic collision.
The mass of the first ball is m1 = 5 kg
The mass of the second ball is m2 = 6 kg.
Let us take the ball moving towards the left as positive and the ball moving towards the right as negative.
The velocity of the first ball before the collision is
[tex]v_o1=-2\text{ m/s}[/tex]
The negative sign indicates that it moves towards the right.
The velocity of the second ball before the collision is
[tex]v_o2=2\text{ m/s}[/tex]
The positive sign indicates that it moves towards the left.
The velocity of the first ball after the collision is
[tex]v_f1=3\text{ m/s}[/tex]
The positive sign indicates that it moves towards the left.
We have to find the velocity of the second ball after the collision.
According to the conservation of momentum,
[tex]m1v_o1+m2v_o2=m1v_f1+m2v_f2[/tex]
Substituting the values, the velocity of the second ball will be
[tex]\begin{gathered} 5\times(-2)+6\times12=5\times3+6\times v_f2 \\ v_f2=\frac{-10+12-15}{6} \\ =-\frac{13}{6} \\ =-2.16\text{ m/s} \end{gathered}[/tex]
Here, the negative sign indicates that the ball is moving towards the right.
Thus, the correct option is 2.16 m/s to the right.
