Given:
There are given the equation:
[tex]N=100e^{kt}[/tex]
Explanation:
From the given exponential function, N represents the number of bacteria and t represents the time.
Then,
According to the question, the value of N is 400 and the value of t is 5.
So,
Put the value of N and t into the above expression to find the value of k.
Then,
[tex]\begin{gathered} N=100e^{kt} \\ 400=100e^{k(5)} \end{gathered}[/tex]
Then,
[tex]\begin{gathered} 400=100e^{k(5)} \\ \frac{400}{100}=\frac{100e^{5k}}{100} \\ 4=e^{5k} \end{gathered}[/tex]
Then,
[tex]\begin{gathered} 4=e^{5k} \\ 5k=ln(4) \\ k=\frac{ln(4)}{5} \end{gathered}[/tex]
So,
The value of k is shown below:
[tex]k=\frac{ln(4)}{5}[/tex]
Final answer:
Hence, the correct option is D.