The model M= -0.711A+206.6 is used to determine the maximum heart rate M of anindividual who is age A.a. Solve for A.b. According to this model, what is the age of an individual whose maximum heart rate is163?

Respuesta :

The given equation models the maximum heart rate of a person:

[tex]M=-0.711A+206.6[/tex]

Now.

a. Solve for A.

First, subtract both sides by 206.6

[tex]\begin{gathered} M-206.6=-0.711A+206.6-206.6 \\ M-206.6=-0.711A \end{gathered}[/tex]

Then, divide both sides by -0.711

[tex]\begin{gathered} \frac{M-206.6}{-0.711}=\frac{-0.711A}{-0.711} \\ \end{gathered}[/tex]

Simplify and get A:

[tex]A=\frac{M-206.6}{-0.711}[/tex]

b. According to this model, what is the age of an individual whose maximum heart rate is 163?

Now, we need to replace = 163

[tex]\begin{gathered} A=\frac{163-206.6}{-0.711} \\ A=61.3 \end{gathered}[/tex]

Hence, the individual would have an age of approximately 61 years.