Given the following quadratic equation:
[tex]x²-7x=-12[/tex]We will rewrite the equation in the standard form as follows:
[tex]x^2-7x+12=0[/tex]Factor the equation:
[tex](x-3)(x-4)=0[/tex]Find the zeros of the equation:
[tex]\begin{gathered} x-3=0\rightarrow x=3 \\ x-4=0\rightarrow x=4 \end{gathered}[/tex]So, the answer will be option a. 3 and 4
