Answer:
Option B is the conclusion that can be made from the given table
The probability of an employee receiving a speeding ticket given that they regularly leave for work early or on time is less than the probability of an employee not receiving a speeding ticket given that they regularly leave for work late.
Explanation:
We need to test the options to know which one of them is correct
A.
The probability of an employee receiving a speeding ticket given that they regularly leave for work late is the same as the probability of an employee not receiving a speeding ticket given that they regularly leave for work early or on time.
[tex]\begin{gathered} \frac{56}{65}=\frac{81}{86} \\ \\ NOT\text{ TRUE} \end{gathered}[/tex]
B.
The probability of an employee receiving a speeding ticket given that they regularly leave for work early or on time is less than the probability of an employee not receiving a speeding ticket given that they regularly leave for work late.
[tex]\begin{gathered} \frac{5}{86}<\frac{9}{65} \\ \\ TRUE \end{gathered}[/tex]
C.
Regularly leaving for work late and receiving a speeding ticket are independent events.
NOT TRUE
D.
Employees who regularly leave for work late are less likely to receive a speeding ticket than employees who regularly leave for work early or on time.
P(Speeding ticket given they leave work late) = 56/65 = 0.8615
P(Speeding ticket given they leave work early or on time) = 5/86 = 0.0581
NOT TRUE
