We are told that the pilot of a plane points his airplane due South and flies with an airspeed of 120 m/s. Simultaneously, there is a steady wind blowing due West with a constant speed of 40 m/s.
a. This can be represented in a diagram by;
To get the direction, consider the right-angled triangle seen in the diagram, with Opposite side of 40 units and Adjacent side of 120 units.
[tex]\begin{gathered} \tan \text{ }\theta\text{ = }\frac{Opposite}{\text{Adjacent}}\text{ = }\frac{40}{120}\text{ = 0.3333} \\ \\ \theta\text{ = }\tan ^{-1}(0.3333)=18.43^0 \end{gathered}[/tex]The direction of the resultant velocity is South 18.43 degrees West
To get the resultant speed, we make use of the concp;
