Given,
The circumference of the wheel is L=48 (pi).
The rate of revolution is
[tex]\omega=\frac{1.5rev}{\sec }[/tex]Let the radius be r.
Thus,
[tex]2\pi r=48\pi[/tex][tex]\Rightarrow r=24\text{ inch}[/tex]Thus the linear speed is:
[tex]v=r\omega=24inch\times\frac{1.5rev}{s}=24\times0.025\times3\pi\text{ m/s}[/tex]Thus,
[tex]v=5.7453\times\frac{3600}{1609}=12.9\text{ mile/hr}[/tex]The answer is :
The linear speed of the wheel is 12.9 miles per hour
