Solution:
Step1:
The triangle under considration is a right angle triangle
Step 2:
One of the required trigonometric ratios that is helpful here is;
[tex]\begin{gathered} \sin \text{ }\theta\text{ = }\frac{\text{opposite}}{\text{hypotenuse}} \\ \\ \sin \text{ 45 = }\frac{13}{x} \end{gathered}[/tex]
Step 3:
Crossing multiplication;
x sin 45 = 13
Step 4:
Dividing both sides by sin 45
[tex]\begin{gathered} x\text{ = }\frac{13}{\sin \text{ 45}} \\ x=13\text{ / }\frac{1}{\sqrt[]{2}} \\ x\text{ = 13 x }\frac{\sqrt[]{2}}{1} \\ x\text{ = 13 }\sqrt[]{2} \end{gathered}[/tex]
Conclusion:
The value of x in the figure given is 13 root 2
