The general equation of the line is
[tex]y=mx+b[/tex]where m is the slope and b the initial point
we can replace the slope 11/12 and the point (60,7)
[tex](7)=\frac{11}{12}(60)+b[/tex]and solve for b
[tex]\begin{gathered} 7-\frac{11}{12}\times60=b \\ \\ b=7-55 \\ b=-48 \end{gathered}[/tex]now, we have the slope and the initial pint, now replace on the general equation and obtain the equation
[tex]y=\frac{11}{12}x-48[/tex]