Given:
[tex]m^2-9=0[/tex]Let's find the solutions to the given equation.
Add 9 to both sides of the equation:
[tex]\begin{gathered} m^2-9+9=0+9 \\ \\ m^2=9 \end{gathered}[/tex]Take the square root of both sides:
[tex]\begin{gathered} \sqrt[]{m^2}=\pm\sqrt[]{9} \\ \\ m=\pm3 \\ \\ m=-3\text{ and m=3} \end{gathered}[/tex]Therefore, the solutions to the equation are:
m = -3 and m = 3
ANSWER:
m = -3 and m = 3
